Hi there! Hopefully this helps!
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First we need to substitute the value of the variable into the expression.
[tex]b^{2}+3(2x-y)[/tex] = [tex]3^{2} + 3 (2(4)-5)[/tex] .
Now we need to solve [tex]3^{2} + 3 (2(4)-5)[/tex].
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[tex]3^{2} + 3 (2(4)-5)[/tex]
First, calculate 3 to the power of 2 and get 9.
[tex]9+3(2\times 4-5)=18[/tex]
Multiply 2 and 4 to get 8.
[tex]9+3(8-5) =18[/tex]
Subtract 5 from 8 to get 3.
[tex]9+3\times 3 =18[/tex]
Multiply 3 and 3 to get 9.
[tex]9+9 =18[/tex].