Complete Question
A scientist believes the concentration of radon gas in the air is greater that the established safe level of 4 pci or less. The scientist tests the composition for 36 days finding an average concentration of 4.4 pci with a sample standard deviation of 1 pci.
a) In testing the scientist's belief, write the appropriate hypotheses:
[tex]H_o:[/tex] Ha:
b) What decision should be made?
Answer:
a
The null hypothesis is [tex]H_o : \mu \le 4 \ pci[/tex]
The alternative hypothesis is [tex]H_a : \mu > 4 \ pci[/tex]
b
There is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 4 \ pci[/tex]
The sample size [tex]n = 36 \ days[/tex]
The sample mean is [tex]\= x = 4.4 \ pci[/tex]
The standard deviation is [tex]\sigma = 1 \ pci[/tex]
The level of significance is [tex]\alpha = 0.05[/tex]
The null hypothesis is [tex]H_o : \mu = 4 \ pci[/tex]
The alternative hypothesis is [tex]H_a : \mu > 4 \ pci[/tex]
Generally the test statistics is mathematically represented as
[tex]t = \frac{ \= x - \mu }{ \frac{ \sigma}{ \sqrt{n} } }[/tex]
=> [tex]t = \frac{ 4.4 - 4 }{ \frac{ 1}{ \sqrt{36} } }[/tex]
=> [tex]t = \frac{ 4.4 - 4 }{ \frac{ 1}{ \sqrt{36} } }[/tex]
=> [tex]t =2.4[/tex]
The p-value is mathematically represented as
[tex]p-value = P(Z > 2.4 )[/tex]
From the z-table
[tex]P(Z > 2.4 ) = 0.008[/tex]
[tex]p-value =0.008[/tex]
So from this obtained value we see that
[tex]p-value < \alpha[/tex] so we reject the null hypothesis
Hence we can conclude that there is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less
