Question

A car is traveling at some speed when it accelerates at 6 m/s2 for 3 seconds. If the car travels 39 meters in this time, how fast was it going before it sped up?

Answer 1

Answer:

4 m/s

Explanation:

Given:

Δx = 39 m

a = 6 m/s²

t = 3 s

Find: v₀

Δx = v₀ t + ½ at²

39 m = v₀ (3 s) + ½ (6 m/s²) (3 s)²

v₀ = 4 m/s