Answer:
2x^3-11x^2+9x+18
Step-by-step explanation:
By multiplying both the binomial and the trinomial given, we obtain a polynomial which contains both as factors. We notice as well that the given trinomial doesn't have 3 as a root (so there is no multiple root x = 3 in the product we obtain:
[tex](-x+3)\,(-2x^2+5x+6)=2\,x^3-5x^2-6x-6x^2+15x+18=2x^3-11x^2+9x+18[/tex]
Then, this new polynomial
[tex]2x^3-11x^2+9x+18[/tex]
has both given polynomials as factors.