Question

Yoooo help

A ball is thrown starting at a time of O and a height of 2 meters. The height of the ball follows the function
H(t)= -4.9t^2 +25t +2. What is the height of the ball at each second from 0 to 5?

Answer 1

Answer:

0 - 1 - 2 - 3 - 4 - 5

2 - 22.1 - 32.4 - 32.9 - 23.6 - 4.5

Step-by-step explanation:

The function is:

• H(t) = -4.9t^2 +25t +2

Calculating the value of H for each value of t from 0 to 5

• H(0) = 2
• H(1) = -4.9*1^2 + 25*1 + 2 = 22.1
• H(2) = - 4.9*2^2 + 25*2 + 2 = 32.4
• H(3) = -4.9*3^2 + 25*3 + 2 = 32.9
• h(4) = -4.9*4^2 + 25*4 + 2 = 23.6
• H(5) = - 4.9*5^2 + 25*5 + 2 = 4.5

Correct answer choice is the 3rd one or C