Answer:
At 336.6K, the density of the liquid is 1.212g/cm³
Explanation:
The density change in a substance with the temperature. As general (But not always applicable) rule, the density decreases with the temperature.
A formula to find density of the liquid of the problem is:
[tex]D = \frac{1.246g/cm^3}{1+8.324x10^{-5}K^{-1}*T}[/tex]
Where D is density and T is absolute temperature (In K).
If we want a density of 1.212g/cm^3:
[tex]1.212g/cm^3 = \frac{1.246g/cm^3}{1+8.324x10^{-5}K^{-1}*T}\\1.212g/cm^3+1.01x10^{-4}g/cm^3K^{-1}*T = 1.246g/cm^3\\1.01x10^{-4}g/cm^3K^{-1}*T =0.034g/cm^3\\T = 336.6K[/tex]
