Question

factorise : 64a cube minus 27b cube minus 144a square b plus 108ab square ​ .


Plz Answer this question

Answer 1

Answer:

$16a(4a^2-9a)+27b^2(4a-b)$

Step-by-step explanation:

The question is not properly formatted, here is a good format for proper understanding and readability

$64a^3-27b^3-144a^2+108ab^2$

let us first collect/ group like terms

$64a^3-144a^2+108ab^2-27b^3$

we can now bring out the common factors we have

$16a(4a^2-9a)+27b^2(4a-b)$

The simplified expression is

$16a(4a^2-9a)+27b^2(4a-b)$