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Determine three consecutive odd integers if the square of the largest integer is 33 less than the sum of the squares of the two smaller integers.

Respuesta :

Three consecutive odd integers
n, n + 2, and n + 4

(n + 4)2 = n2 + (n + 2)2 - 345
n2 + 8n + 16 = n2 + n2 + 4n + 4 - 345
n2 + 8n +16 = 2n2 + 4n - 341
0 = n2 - 4n - 357
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