Answer:
1.63×10¹⁰ L.
Explanation:
We'll begin by calculating the number of mole in 125 g of silver (ii) oxide, AgO. This can be obtained as follow:
Mass of AgO = 125 g
Molar mass of AgO = 108 + 16 = 124 g/mol.
Mole of AgO =?
Mole = mass /Molar mass
Mole of AgO = 125 /124
Mole of AgO = 1.01 moles.
Next, we shall convert 6.19×10¯⁵ μmol/L to mol/L. This can be obtained as follow:
1 μmol/L = 1×10¯⁶ mol/L
Therefore,
6.19×10¯⁵ μmol/L = 6.19×10¯⁵ × 1×10¯⁶ = 6.19×10¯¹¹ mol/L
Finally, we shall determine the volume as follow:
Molarity = 6.19×10¯¹¹ mol/L
Mole of AgO = 1.01 moles
Volume =?
Molarity = mole /Volume
6.19×10¯¹¹ = 1.01/Volume
Cross multiply
6.19×10¯¹¹ × volume = 1.01
Divide both side by 6.19×10¯¹¹
Volume = 1.01/6.19×10¯¹¹
Volume = 1.63×10¹⁰ L
Therefore, the volume of the solution is 1.63×10¹⁰ L
