the third term of the geometric sequence with first term = 1/4 and common ratio r = -2 is 1
We have a geometric sequence in which the first term is [tex]\frac{1}{4}[/tex] and the common ratio is -2.
We have to find the third term of this geometric sequence.
The formula to find the [tex]n^{th}[/tex] term of a geometric sequence with first term [tex]a_{1}[/tex] and common ratio r is -
[tex]a_{n} =a_{1} r^{n-1}[/tex]
In our question, [tex]a_{1}[/tex] = [tex]\frac{1}{4}[/tex] and r = -2 and n =3.
Substituting the values, we get -
[tex]a_{3} =\frac{1}{4}(-2)^{3-1} = \frac{1}{4} (-2)^{2} =\frac{1}{4}\times4=1[/tex]
Hence, the third term of the geometric sequence with first term = 1/4 and common ratio r = -2 is 1.
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