Question

A student determines the mass of a metal rod to be 39.35 g. it is places in 10.00 mL of water, and the water level rises to 15.00 mL. What is the density of the rod?

Answer 1

Answer:$\rho=7.87g/mL$

Explanation:

Hello,

In this case, we are analyzing a problem in which the Archimedes principle is considered, thus, as the volume of the metal rod is determined by the difference between the mass of the water and the mass of the water and the rod:

$V_{rod}=15.00mL-10.00mL=5.00mL$

In such a way, the density turns out:

$\rho =\frac{m_{rod}}{V_{rod}}=\frac{39.35g}{5.00mL} \\ \\\rho=7.87g/mL$

Regards.