Question

Two cars collide head on while each is traveling at 60km/h .Suppose all their kinetic energy is transformed into the thermal energy of the wrecks. What is the temperature increase of each car?You can assume that each car's specific heat is that of iron.

Answer 1

Answer:

The  temperature rise $\Delta T = 0.3088 \ ^oC$

Explanation:

From the question we are told that

  The  speed is  $v = 60 \ km /h = 16.67 \ m/s$

 

Generally according to the law of energy conservation we have that

   The  kinetic energy  =  increase in the internal energy of the car

i,e          $\frac{1}{2} * m * v^2 = m * c_p * \Delta T$

Here  $c_p$ of  iron is  $c_p = 450 \ J/kg K$

      So  

            $0.5 * 16.67^2 = 450 * \Delta T$

=>         $\Delta T = 0.3088 \ ^oC$

     

Answer 2

The temperature increase of each car will be 0.3088 °C.

What is temperature?

Temperature directs to the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.

The given data in the problem is;

v is the velocity= 60 km/h=16.67 m/sec

ΔT is the temperature difference=?

$\rm c_P$ is the specific heat of iron=450 J/KgK

From the law of energy conservation of the energy, the kinetic energy is equal to the increase in the internal energy of the car.

$\rm KE=\triangle E \\\\\ \frac{1}{2} mv^2=mc_p \triangle T \\\\ \triangle T=\frac{v^2}{2C_p} \\\\\ \triangle T=\frac{(16.67)^2}{2\times 450} \\\\ \triangle T=0.3088 ^0\C$

Hence the temperature increase of each car will be 0.3088 °C.

To learn more about the temperature refer to the link;

https://brainly.com/question/7510619Δ