Answer:
The question is missing the values, I found a possible matching question:
a city has a population of 380,000 people. suppose that each year the population grows by 7.5%. what will be the population after 6 years
Answer:
After 6 years, the population will be 586, 455 people
Step-by-step explanation:
This growth is similar to the growth of an invested amount of money, which is compounded annually, yielding a future value, when it increases by a certain interest rate. Hence the formula for compound interest is used to determine the population after 6 years as follows:
[tex]FV = PV (1+ \frac{r}{n})^({n \times t})[/tex]
where
FV = future value = population after 6 years = ???
PV = present value = current  population = 380,000 people
r = interest rate = growth rate = 7.5% = 7.5/100 = 0.075
n = number of compounding periods per year = annually = 1
t = time of growth = 6 years
[tex]FV = 380,000 (1+ \frac{0.075}{1})^({1 \times 6})\\FV = 380,000 (1.075)^{6}\\FV= 380,000 (1.5433015256)\\FV = 586,454.58\\FV= 586,455\ people[/tex]
Therefore, after 6 years, the population will be 586, 455 people
