Answer:
[tex]Cp=0.552\frac{J}{g\°C}[/tex]
Explanation:
Hello,
In this case, the formula to compute the required heat based on the mass, specific heat and change in temperature is widely known as:
[tex]Q=mCp\Delta T[/tex]
In such a way, since we are asked to compute the specific heat, we solve for it as shown below:
[tex]Cp=\frac{Q}{m\Delta T}=\frac{1870J}{75.01g*45.2\°C} \\ \\Cp=0.552\frac{J}{g\°C}[/tex]
Best regards.
The specific heat of the metal exhibiting 45.2 [tex]\rm ^\circ C[/tex] temperature change has been 0.55 J/g.[tex]\rm ^\circ C[/tex].
The specific heat can be defined as the amount of heat required to raise the temperature of 1 gram of a substance by 1 degree Celsius.
The expression can be given as:
Q = mc[tex]\Delta[/tex]T
where, Q = heat required = 1870 J
m = mass = 75.01 g
c = specific heat capacity
[tex]\Delta[/tex]T = change in temperature = 45.2 [tex]\rm ^\circ C[/tex]
1870 J = 75.01 g [tex]\times[/tex] c [tex]\times[/tex] 45.2 [tex]\rm ^\circ C[/tex]
c = [tex]\rm \dfrac{1870}{75.01\;\times\;45.2}[/tex]
c = 0.55 J/g.[tex]\rm ^\circ C[/tex]
The specific heat of the metal exhibiting 45.2 [tex]\rm ^\circ C[/tex] temperature change has been 0.55 J/g.[tex]\rm ^\circ C[/tex].
For more information about the specific heat capacity, refer to the link:
https://brainly.com/question/13369050
