Answer:
Plane A / 7.62 mi away
Step-by-step explanation:
We have to calculate the distance of each plane from the airport.
In other to do this, we would use the trigonometric function of Sine
sin θ = Opposite/Hypotenuse
For Plane A
Plane A departs at a 41° angle from the runway
sin θ = Opposite/Hypotenuse
θ = 41°
Distance from the ground = Opposite = 5 miles
Hypotenuse = ???
sin 41° = 5 miles/Hypotenuse
sin 41° × Hypotenuse = 5 miles
Hypotenuse = 5 miles/sin 41°
Hypotenuse = 7.6212654335 miles
Approximately to the nearest hundredth ≈ 7.62 miles
For Plane B
Plane B departs at a 43° from the runway
sin θ = Opposite/Hypotenuse
θ = 43°
Distance from the ground = Opposite = 5 miles
Hypotenuse = ???
sin 43° = 5 miles/Hypotenuse
sin 43° × Hypotenuse = 5 miles
Hypotenuse = 5 miles/sin 43°
Hypotenuse = 7.3313959282 miles
Approximately to the nearest hundredth ≈ 7.33 miles
From the above calculation, we can see that Plane A what 7.62 miles away from the airport while Plane b was 7.33 miles away from the airport.
Therefore Plane A was farther away from the airport (7.62 miles away) when it was 5 miles from the ground.
Answer:
Plane A / 7.62 mi away
Step-by-step explanation:
I got it right on the test
