In a simple random sample of 800 people age 20 and over in a certain country, the proportion with a certain disease was found to be 0.165 (or 16.5%). Complete parts (a) through (c) below. a. What is the standard error of the estimate of the proportion of all people in the country age 20 and over with the disease? (Round to four decimal places as needed.) b. Find the margin of error, using a 95% confidence level, for estimating this proportion. m=______(round to three decimal places as? needed.)c. Report the 95% confidence interval for the proportion of all Americans age 20 and over with diabetes.

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Answer and Explanation:

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I'm calculating standard error we used the formula standard deviation/√number of samples. Standard deviation is not known and so it was first calculated

Margin of error and confidence intervals were also calculated using their formulas

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