Answer:
Perimeter of the shape = (14+5π )inches
Step-by-step explanation:
The shape is made up of a semicircle and a right angled triangle.
Perimeter of the shape = perimeter of a semicircle + perimeter of the right angle triangle.
Since perimeter of a circle = 2πr
Perimeter of a semicircle = 2πr/2 = πr wherr r is the radius
r = 10in/2 = 5in
Perimeter of the semicircle = 5π in
Perimeter of a triangle = s1+s2+s3 where s1, s2 and s3 are the sides of the triangle.
We only have 2 sdies of the triangle, hence we need to get the third side using pythagoras theorem.
let s1 = 10in, s2 = 6in
10² = 6²+s3²
s3 = √10²-6²
s3 = √100-36
s3 = √64
s3 = 8in
Perimeter of the triangle = 10in+6in+8in = 24in
Perimeter of the shape = (24in + 5π in) - 10in (10 in was subtracted since it is common to both shapes)
Perimeter of the shape = (14+5π )inches
