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Answer: so
60% are blue.
3/5 are blue.
2/5 are red.
There are 3 blue fish and 2 red fish.
Using a system of linear equations, the number of blue and red fishes in the aquarium are 3 and 2 respectively.
Let :
- Number of red fishes = r
- Number of Blue fishes = b
Number of red fishes :
- r = b - 1 - - - - (1)
- b = 0.6(r + b) - - - - (2)
Substitute (1) into (2)
b = 0.6(b - 1 + b)
b = 0.6(2b - 1)
b = 1.2b - 0.6
1.2b - b = 0.6
0.2b = 0.6
b = 3
From (1) :
r = 3 - 1 = 2
Therefore, there are 3 blue fishes and 2 red fishes
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