Water flows through a valve with inlet and outlet velocities of 3 m/s. If the loss coefficient of the valve is 2.0, and the specific weight of water is 9800 N/m3, the pressure drop across the valve is most nearly:

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Answer:

The value is [tex]\delta P = 9000 \ Pa[/tex]

Explanation:

From the question we are told that

    The inlet and outlet velocity is [tex]v = 3 \ m/s[/tex]

     The  loss coefficient is  [tex]k = 2[/tex]

      Th specific weight of water  is  [tex]w = 9800 \ N/m^3[/tex]

Generally the pressure drop across the valve is mathematically represented as

       [tex]\delta P = \frac{1}{2} * k * \rho * v^2[/tex]

Here  [tex]\rho[/tex] is the density which is mathematically represented as

      [tex]\rho = \frac{w}{g}[/tex]

=>    [tex]\rho = \frac{9800}{9.8}[/tex]

=>   [tex]\rho = 1000 \ kg/m^3[/tex]

So

    [tex]\delta P = \frac{1}{2} * 2* 1000 * 3^2[/tex]

    [tex]\delta P = 9000 \ Pa[/tex]

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