Respuesta :

im pretty sure that it is

i

Answer:

i

Step-by-step explanation:

[tex] \huge {i}^{37} \\ \huge= {i}^{36} \times i \\ \huge = ( {i}^{2})^{18} \times i \\\huge = ( - 1) ^{18} \times i \\ \huge = 1 \times i \\ \huge = i \\ \\\huge \therefore {i}^{37} = i[/tex]