Question

Aaliyah is drawing a ball from one bag and a tile from another bag. The first bag contains 4 green balls and 4 yellow balls. The second bag
contains tiles numbered 1 through 5.
What is the probability that she draws a green ball and a tile numbered with 4?

Answer 1

Step-by-step explanation:

P(green AND 4)

= P(green) × P(4)

= (4/8) × (1/5)

= 1/10

Answer 2

Using probabilities of independent events, it is found that there is a 0.1 = 10% probability that she draws a green ball and a tile numbered with 4.

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• A probability is the number of desired outcomes divided by the number of total outcomes.
• If two events, A and B, are independent, the probability of both happening together is the multiplication of the probabilities of each happening.

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• Event A: Green ball, 4 out of the 8 balls are green, thus, $P(A) = \frac{4}{8} = 0.5$
• Event B: Tile numbered with 4, which is one of the five, thus, $P(B) = \frac{1}{5} = 0.2$

The probability of both events is given by:

$P(A \cap B) = P(A) \times P(B) = 0.5(0.2) = 0.1$

0.1 = 10% probability that she draws a green ball and a tile numbered with 4.

A similar problem is given at https://brainly.com/question/24174994