Question

Solve the following numerical problems. a) A load of 400N is liſted up by an effort of 100N. If load distance is 20cm, what will be the effort distance? (Ans 80cm)
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Answer 1

Answer:

Solution

Load(L)=400

Effort(E)=100

Load distance (Ld)=20cm

Effort distance(Ed)=?

Now,from the principle of equilibrium

L×Ld=E×Ed

or,Ed=L×Ld/E

or,Ed=400×20/100

:.Ed=80cm and

Therefore,the effort distance will be 80cm