Question

factorise : 64a cube minus 27b cube minus 144a square b plus 108ab square ​ .


Plz Answer this question

Answer 1

Answer:

The answer is $4a(16a^2+27b^2)-3b(9b^2+48b)$

Step-by-step explanation:

step one:

let us re-write the expression in mathematical terms for clarity

we have the expression stated  below

$64a^3-27b^3-144b^2+108ab^2$    

step two:

We are going to collect like terms before factorization we have

    $64a^3+108ab^2-27b^3-144b^2$

We can now factorize the expression we have  

$4a(16a^2+27b^2)-3b(9b^2+48b)$