Answer:
X is in NP and Y is in NP-HARD ( A )
Explanation:
X is in NP and Y is in NP-HARD can be inferred from the previous statement made in the problem above because problem decision X can be in NP if it can BE reducible to a 3-SAT polynomial real time, if that can be achieved then 3SAT will be in NP since SAT is in NP as well.
also problem decision Y can be in NP-HARD if 3SAT can be reducible to it in polynomial time as well hence option A is the correct option