Could someone please explain the meaning of this. I've tried almost every possible way of removing one 2 but It's not working for every number. ───── Find the number of even divisors Steps: ──────────────── Step 1: Find the prime factorization of the given number. ──────────── Step 2: Remove one “2” from the factors. ───────────────────── Step 3: Calculate the number of factors of the remaining number. ──────

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Answer:

see below (I hope this helps!)

Step-by-step explanation:

Let's take the number 10 for example. Its prime factorization is 2 * 5. Removing the 2 leaves us with just 5, and since 5 has 2 factors, we know that 10 has 2 even divisors. I think that the reason why it's not working for you is that you are using odd numbers, keep in mind that if a number has an even divisor, it is automatically even so in this case, we're talking about even numbers only.

A few more examples:

Number = 30, prime factorization = 2 * 3  * 5, removing a 2 leaves us with 3 * 5 = 15, 15 has 4 factors so we know that 30 has 4 even divisors.

Number = 26, prime factorization = 2 * 13, removing a 2 leaves us with 13 and 13 has 2 factors so we know that 26 has 2 even divisors.

Answer:

Let's take the number 10 for example. Its prime factorization is 2 * 5. Removing the 2 leaves us with just 5, and since 5 has 2 factors, we know that 10 has 2 even divisors. I think that the reason why it's not working for you is that you are using odd numbers, keep in mind that if a number has an even divisor, it is automatically even so in this case, we're talking about even numbers only.

A few more examples:

Number = 30, prime factorization = 2 * 3  * 5, removing a 2 leaves us with 3 * 5 = 15, 15 has 4 factors so we know that 30 has 4 even divisors.

Number = 26, prime factorization = 2 * 13, removing a 2 leaves us with 13 and 13 has 2 factors so we know that 26 has 2 even divisors.

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