Question

If m<1 is three less than twice the measure of <2, and <1 and <2 are supplementary angles, find each angle
measure.​

Answer 1

Step-by-step explanation:

Hey there!!

Let angle 2 be x then,

measure of angle 1 is three less than twice of angle 2 = 2x-3.

Now, we have.

Measure of supplementary angle is 180°.

Angle 1 + angle 2 = 180°

x+(2x - 3)= 180°

3x -3=180°

3x= 180°+3°

$x = \frac{183}{3}$

Therefore, x = 61°.

Now, angle 2 = 61°

angle 1 = (61×2-3)= 119°.

check (119°+61°=180°).

Hope it helps...