Question

How many electrons would have to be removed from a coin to leave it with a charge of +1.0 10-7 C?

Answer 1

Answer:

$n=6.25\times 10^{11}$

Explanation:

We need to find the number of electrons that would have to be removed from a coin to leave it with a charge of $+10^{-7}\ C$. Then the number of electrons be n. Using quantization of electric charge as :

q = ne

e is charge on an electron

$n=\dfrac{q}{e}\\\\n=\dfrac{10^{-7}}{1.6\times 10^{-19}}\\\\n=6.25\times 10^{11}$

So, the number of electrons are $6.25\times 10^{11}$.