Question

Graph the solution of 7x+3<−4 or 2x−3≥9

Answer 1

Answer:

Step-by-step explanation:

To do this you would simplify both sides.

For the first one:

             $7x+3<-4$

             $7x<-7$        (subtract 3 from both sides)

              $x<-1$         (divide 7 from both sides)

and for the second one:

              $2x-3\geq 9$

               $2x\geq 12$        (add 3 to both sides)

              $x\geq 6$             (divide 2 from both sides)

When you graph these they will look like these pictures    

Answer 2

Answer:

$x<-1$ and $x\geq6$

Step-by-step explanation:

$\bf 7x+3<-4$

You must subtract 3 from both sides.

$7x+3-3<-4-3$

After subtracting, we got

$7x<-7$

Let's make it into a fraction and divide

$\frac{7x}{7}<\frac{-7}{7}$

Now we got the answer

$x<-1$

$\bf 2x-3\geq 9$

You must add 3 to both sides.

$2x-3+3\geq 9+3$

After adding, we got

$2x\geq 12$

Let's make it into a fraction and divide

$\frac{2x}{2} \geq \frac{12}{2}$

Now we got the answer

$x\geq 6$

Your answer is $\bf x<-1$ or $\bf x\geq 6$.