Respuesta :
Answer:
v = 6.38 m/s
Explanation:
discharge Q = 500 L / 6.5 min
flow through pipe is 1.6 cm x (1 m/100 cm ) = 0.016 m
using the flow rate formula Q = A * v
where A = area, v = velocity
the speed of water in the pipe = v = Q / A
500 L 1 m³ 1 min π (0.016 m)²
v = ---------- x -------- x ------------ ÷ --------------------
6.5 min 10³ L 60 sec 4
v = 6.38 m/s
The speed of the water is "12.95 m/s".
According to the question,
Volume,
- V = 500 L
= [tex]500\times 10^{-3} \ m^3[/tex]
Time,
- t = 3.2 min
= [tex]3.2\times 60[/tex]
= [tex]192 \ s[/tex]
Diameter,
- d = 1.6 cm
= 0.016 m
As we know,
Area of cross-section of pipe will be:
→ [tex]A = \pi (\frac{d}{2} )^2[/tex]
[tex]= 3.14\times (\frac{0.016}{2} )^2[/tex]
[tex]= 2.01\times 10^{-4} \ m^2[/tex]
Flow rate is:
→ [tex]\frac{V}{t} = Av[/tex]
[tex]v = \frac{V}{At}[/tex]
[tex]= \frac{500\times 10^{-3}}{2.01\times 10^{-4}\times 192}[/tex]
[tex]= 12.95 \ m/s[/tex]
Thus the above approach is right.
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