What minimum separation between two parallel plates of glass (nglass =1.5) produces constructive interference for the reflected light with a 710 nm wavelength if the gap between the plates is filled with oil with noil =1.8?

Respuesta :

Answer:

The  value is  [tex]t = 9.861 *10^{-8} \ m[/tex]

Explanation:

From the question we are told that

   The  refractive index of glass is [tex]n_{glass} = 1.5[/tex]

     The wavelength is  [tex]\lambda = 710 nm = \frac{710}{1 * 10^9} = 710*10^{-9} \ m[/tex]

      The  refractive index of  oil is  [tex]n_{oil} = 1.8[/tex]

Generally the condition for refractive index is  mathematically represented as

     [tex]2 * t = [m + \frac{1}{2} ] \frac{\lambda}{n_{oil}}[/tex]

Where  t is the separation between two parallel plates of glass , now at minimum  m which is the  order of maxima produced is   =  0

So

     [tex]2 * t = [0 + \frac{1}{2} ] \frac{710 *10^{-9}}{1.8}[/tex]

    [tex]t = 9.861 *10^{-8} \ m[/tex]

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