Question

The perimeter of a rectangle is 38 units. The length is 13 units longer than the width. What are the dimensions of the rectangle?
A 18 by 5
B. 12 by 7
Oc is by a
0.16 by

Answer 1

Answer:

D (Presumably)

16 by 3

Step-by-step explanation:

The perimeter of a rectangle is the two lengths added with the two widths. In a formula, this is:

$P=2l+2w$

Where l is the length and w is the width.

We are told the length is 13 units longer than the width. In other words:

$l=w+13$

We also already know that the perimeter is 38 units. So, let's substitute P for 38 and l for (w+13) to solve for w:

$P=2l+2w\\38=2(w+13)+2w$

Distribute:

$38=2w+26+2w$

Combine like terms:

$38=4w+26$

Subtract 26 from both sides:

$12=4w$

Divide both sides by 4:

$w=3$

Thus, the width is 3 units.

Since the length is 13 units longer than the width, the length is 16 units.