Question

Question 5 At 12:00 pm, a spaceship is at position ⎡⎣324⎤⎦ km ⎣ ⎢ ⎡ ​ 3 2 4 ​ ⎦ ⎥ ⎤ ​ km away from the origin with respect to some 3 dimensional coordinate system. The ship is travelling with velocity ⎡⎣−12−3⎤⎦ km/h ⎣ ⎢ ⎡ ​ −1 2 −3 ​ ⎦ ⎥ ⎤ ​ km/h What is the location of the spaceship after 2 hours have passed

Answer 1

Answer:

[1, 6, -2]

Explanation:

Given the following :

Initial Position of spaceship : [3 2 4] km

Velocity of spaceship : [-1 2 - 3] km/hr

Location of ship after two hours have passed :

Distance moved by spaceship :

Velocity × time

[-1 2 -3] × 2 = [-2 4 -6]

Location of ship after two hours :

Initial position + distance moved

[3 2 4] + [-2 4 -6] = [3 + (-2)], [2 + 4], [4 + (-6)]

= [3-2, 2+4, 4-6] = [1, 6, -2]

Answer 2

The location of the spaceship after 2 hours have passed is [1, 6, -2]

Calculation of the location:

Since

Initial Position of spaceship : [3 2 4] km

Velocity of spaceship : [-1 2 - 3] km/hr

Now

Location of the ship after two hours should have passed

So,

Distance moved by spaceship should be

= Velocity × time

= [-1 2 -3] × 2

= [-2 4 -6]

Now

Location of ship after two hours should be

= Initial position + distance moved

= [3 2 4] + [-2 4 -6]

= [3 + (-2)], [2 + 4], [4 + (-6)]

= [3-2, 2+4, 4-6]

= [1, 6, -2]

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