Question

For an experiment with 3 groups of 10 participants in each group. Fcrit for alpha 0.05=_________

a. 3.35
b. 2.35
c. 5
d. 12

Answer 1

Answer:

a. 3.35

Step-by-step explanation:

Given that :

an experiment with 3 groups  consist of 10 participant in each group.

This implies that:

number of group k = 3

number of participants n = 10

N = nk

N =  10 × 3 = 30

The degree of freedom within can be calculate as:

dfw = N - k

dfw = 30 - 3

dfw = 27

The degree of freedom for the critical value

dfc = n- 1

dfc = 3 - 1

dfc = 2

At the level of significance ∝ = 0.05

The F critical value from the standard normal F table

i.e

$F_{critical { (2, 27)}=$ 3.35