Answer:
5.76 N/m
Explanation:
From the question,
F = BILsinФ...................... Equation 1
and then,
F/L = BIsinФ.................. Equation 2
Where F/L = force per meter, I = current, B = magnetic field, Ф = angle.
Given: B = 0.9 T, I = 6.4 A, and Ф = 90° (Perpendicular)
Subtitute these values into equation 2
F/L = 0.9(6.4)(sin90°)
F/L = 5.76 N/m
The force per meter of length on a straight wire will be 5.76 N/m.
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. the magnetic force is obtained it is the field felt around a moving electric charge.
The given data in the problem si;
B is the megnetic field=0.9 T
I is the current = 6.4 A,
Ф is the angle = 90° (Perpendicular)
The megnetic field is found as;
[tex]\rm F= BILsin \phi \\\\ \frac{F}{L} =BIsin\phi \\\\ \frac{F}{L} =0.9 \times 6.4 \times sin 90^0\\\\ \frac{F}{L} =5.76 / N/m[/tex]
Hence the force per meter of length on a straight wire will be 5.76 N/m.
To learn more about the magnetic field refer to the link;
https://brainly.com/question/19542022
