Question

If you wish to detect details of the size of atoms (about 1 ✕ 10−10 m) with electromagnetic radiation, it must have a wavelength of about this size.
(a) What is its frequency?
(b) What type of electromagnetic radiation might this be?

Answer 1

Answer:

a) 3×10^18 Hz

b) The electromagnetic wave is an x-ray

Explanation:

We know that the speed of an electromagnetic wave is given by;

c= λf

Where;

c= speed of electromagnetic waves = 3×10^8 ms-1

f= frequency of electromagnetic waves= the unknown

λ = wavelength of the electromagnetic wave= 1 ×10^-10 m

Hence;

f = c/λ= 3×10^8/ 1×10^-10

f= 3×10^18 Hz

b) The electromagnetic wave is an x-ray.

Answer 2

(a) The frequency of the electromagnetic radiation is $3\times 10^{18} \ Hz$

(b)  The electromagnetic radiation is ultra violet ray.

The given parameters;

• distance of the atom, λ = 1 x 10⁻¹⁰ m

The frequency of the electromagnetic radiation is calculated as follows;

$c =f \lambda \\\\f = \frac{c}{\lambda} \\\\f = \frac{3\times 10^8}{1\times 10^{-10}} \\\\f = 3\times 10^{18} \ Hz$

The frequency range of ultra violet ray is between 10¹⁴ to 10¹⁸ m.

Thus, the electromagnetic radiation is ultra violet ray.

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