Question

the sum of three consecutive integers is 330 what is the smallest of these integers?? will give brainliest

Answer 1

Answer:

109

Step-by-step explanation:

Three consecutive integers:

• x, x+1, x+2

Sum of them:

• x+(x+1)+(x+2) = 330
• 3x + 3 = 330
• 3x= 327
• x= 327/3
• x= 109

The smallest integer out of three is 109

Answer 2

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3 consecutive integers = x+(x+1)+(x+2) or 3x+3 (x is the smallest number)

(Consecutive means one after another)

So 3x+3 = 330.

Now subtract 3 from both sides.

(3x-3)=3x

(330-3)=327

The left side is 3x and the right side is 327.

The equation now is 3x=327.

Now divide each side by 3 (so x is isolated)

3x÷3=x

327÷3=109

The left side is x and the right side is 109.

The final equation is x=109.

Since x is the smallest of these integers we don't have to do anything else.

Okay, so let's check the answer now. 109+110+111=330.

So the smallest of the 3 consecutive numbers is 109.

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