Answer:
The velocity component v is [tex]-6axy+2by^2+f(x)[/tex]
Explanation:
Given that,
The velocity component of a steady, two-dimensional
[tex]u=3ax^2-2bxy[/tex]
We need to calculate the function of x
Using given equation
[tex]u=3ax^2-2bxy[/tex]
Where, a and b is constant
On differential
[tex]\dfrac{du}{dx}=6ax-2by[/tex]
We need to calculate the velocity component v
Using equation of velocity
[tex]\dfrac{dv}{dy}=-\dfrac{du}{dx}-\dfrac{dw}{dz}[/tex]
Put the value into the formula
[tex]\dfrac{dv}{dy}=-6ax+2by-0[/tex]
Now, on integration w.r.t y
[tex]v=-6axy+2by^2+f(x)[/tex]
Hence, The velocity component v is [tex]-6axy+2by^2+f(x)[/tex]