Question

Two parallel very long straight wires carrying current of 5A each are kept at a separation of 1m. If the currents are in the same direction, the force per unit length between them is __________

Answer 1

Answer:

The force per unit between the two parallel wires with same current flowing in the same direction is 5 x 10⁻⁶ N/m repulsive force.

Explanation:

Given;

current though the two parallel wires, I₁ and I₂ = 5A

distance between the two wires, R = 1 m

The force per unit of the wires is calculated as;

$\frac{F}{L} = \frac{\mu_o I_1I_2}{2\pi R}$

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

Substitute in the given values into the equation and determine the force per unit length (F/L).

$\frac{F}{L} = \frac{\mu_o I_1I_2}{2\pi R} \\\\ \frac{F}{L} = \frac{4\pi *10^{-7}*5*5}{2\pi *1}\\\\ \frac{F}{L} = 5*10^{-6} \ N/m \ (repulsive)$

Therefore , the force per unit between the two parallel wires with same current flowing in the same direction is 5 x 10⁻⁶ N/m repulsive force.