solve for the right triangle given only one side and angle
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Answer:
CD = √11 and CE = √11
Step-by-step explanation:
We know that m∠D is 45° (by using the sum of interior angles in a triangle) so therefore, ΔDCE is a 45 - 45 - 90 triangle (the 45, 45, and 90 refer to the angle measures). The ratio of sides in a 45 - 45 - 90 triangle is 1 : 1 : √2 where the 1s are the sides and the √2 is the hypotenuse. We need to solve for x in x : x : √22. If you notice that √22 = √2 * √11, we can use this to find x, therefore, x = 1 * √11 = √11 so CD = √11 and CE = √11.
Answer:
[tex]\huge \boxed{CD =\sqrt{11} } \\ \\ \huge \boxed{CE =\sqrt{11} }[/tex]
Step-by-step explanation:
The triangle is a right triangle.
We can apply trigonometric functions to solve for the missing sides.
sin θ = opp/hyp
sin 45 = CD /√22
Multiply both sides by √22.
√22 sin 45 = CD
√11 = CD
cos θ = adj/hyp
cos 45 = CE /√22
Multiply both sides by √22.
√22 cos 45 = CE
√11 = CE