Question

A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the bob's mass is doubled, approximately what will the pendulum's new period be?
A: T/2
B: T
C: sqrt(2)*T
D: 2T

Answer 1

Answer:

B. T

Explanation:

This is because the mass of the Bob does no relate to the period as given by the relationship

T = 2π(√L/g) so double mass is still T

Answer 2

Answer:

The correct option is (B).

Explanation:

The time period of a pendulum is given by :

$T=2\pi \sqrt{\dfrac{l}{g}}$

l is the length of the pendulum

g is acceleration due to gravity

It is very clear that the time period is independent of the mass of the bob. If the mass of the bob is doubled, the time period of the pendulum remains the same i.e. T. Hence, the correct option is (B).