Answer: [tex]1\dfrac{29}{60}\text{ minutes}[/tex]
Step-by-step explanation:
Given: A total eclipse solar eclipse in 2003 lasted [tex]5\dfrac{3}{20}[/tex] minutes
[tex]=\dfrac{5(20)+3}{20}=\dfrac{103}{20}\text{ minutes}[/tex]
& a total eclipse solar eclipse in 2005 lasted [tex]3\dfrac{2}{3}[/tex]minutes
[tex]=\dfrac{3(3)+2}{3}=\dfrac{11}{3}\text{ minutes}[/tex]
Difference= [tex]\dfrac{103}{20}-\dfrac{11}{3}=\dfrac{103\times3-11\times20}{60}[/tex]
[tex]=\dfrac{309-220}{60}\\\\=\dfrac{89}{60}\text{ minutes}\\\\=1\dfrac{29}{60}\text{ minutes}[/tex]
So, 2003 solar eclipse was [tex]1\dfrac{29}{60}\text{ minutes}[/tex] longer than solar eclipse in 2005.