Question

A 0.145 kg baseball pitched at 33.m/s is hit on a horizontal line drive straight back at the pitcher at 46.0 m/s. If the contact time between bat and ball is 5.70×10−3 s, calculate the magnitude of the force (assumed to be constant) exerted on the ball by the bat.

Answer 1

Answer:

F = 2009.64 N

Explanation:

It is given that,

Mass of a baseball, m = 0.145 kg

Initial speed if the baseball, u = 33 m/s

It hit on a horizontal line drive straight back at the pitcher at 46.0 m/s, final velocity, v = -46 m/s

Time of contact between the bat and the ball is $t=5.7\times 10^{-3}\ s$

We need to find the magnitude of the force exerted by the ball on the bat. It can be calculated using impulse-momentum theorem. So,

$Ft=m(v-u)\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.145\times (-46-33)}{5.7\times 10^{-3}}\\\\F=-2009.64\ N$

So, the magnitude of force exerted on the ball by the bat is 2009.64 N.