I need urgent help with the question. Can someone please give full working out of the attached question
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Answer:
2x-2
Step-by-step explanation:
Being specifically asked to rationalise the denominator we focus on it as required.
To rationalise a term it has to be multiplied by its inverse.
The inverse of
[tex] \sqrt{x} - \sqrt{2 - x} [/tex]
is
[tex] \sqrt{x} + \sqrt{2 - x} [/tex]
Multiplying this two vives us a difference of two squares
[tex] {( \sqrt{x} })^{2} - {( \sqrt{2 - x} )}^{2} [/tex]
which gives us
x-(2-x)
=2x-2