Question

What is the area of this triangle on a Coordinate Grid?

Triangle IJK, with vertices I(3,-7), J(7,-4), and K(4,-2), is drawn inside a rectangle

Answer 1

Answer: 8.5 sq. units.

Step-by-step explanation:

Formula:

Area of triangle : $\dfrac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$

Given: Triangle IJK, with vertices I(3,-7), J(7,-4), and K(4,-2)

Then, Area of triangle  IJK = $\dfrac{1}{2}|3(-4-(-2))+7(-2-(-7))+4(-7-(-4))|$

$\dfrac{1}{2}|3(-2)+7(5)+4(-3)|\\\\=\dfrac{1}{2}|-6+35-12|\\\\=\dfrac{1}{2}(17)\\\\=8.5\text{ sq. units}$

Hence, the area of this triangle  IJK on a Coordinate Grid = 8.5 sq. units.