Question

Find the value of sin(θ) for an angle theta in standard position with a terminal ray that passes through the point (4,-3)

Answer 1

Answer:

$\dfrac{-3}{5}$

Step-by-step explanation:

It is given that a terminal ray that passes through the point (4,-3).

x = 4

y = -3

Using Pythagoras theorem, the value of hypotenuse is

$r=\sqrt{x^2+y^2}$  

$r=\sqrt{(-3)^2+(4)^2}$  

$r=\sqrt{9+16}$  

$r=\sqrt{25}$  

$r=5$

We, know that

$\sin \theta = \dfrac{y}{r}$

$\sin \theta = \dfrac{-3}{5}$

Therefore, the value of $\sin \theta$ is $\dfrac{-3}{5}$.