What is the distance from the origin to point A graphed on the complex plane below?
|5|
|13|
9
13

Answer:
√13
Step-by-step explanation:
(-3, -2) (0, 0)
distance √(9 + 4) = √13
The distance from the origin to the point A is [tex]\sqrt{13}[/tex] unit.
Let, the co-ordinates of two points in 2D plane are [tex](x_{1} ,y_{1} )[/tex] & [tex](x_{2}, y_{2} )[/tex]
Then the distance between this two points be d (say)
Therefore, [tex]d=\sqrt{(x_{2}- x_{1}) ^{2}+ (y_{2} -y_{1} )^{2} }[/tex]
The co-ordinate of point A in the graph is (-3, -2)
The co-ordinate of origin is (0, 0)
∴ The distance between (0, 0) & (-3, -2) is = [tex]\sqrt{((-3)-0) ^{2}+ ((-2) -0 )^{2} }[/tex]
= [tex]\sqrt{(-3)^{2}+(-2)^{2} }[/tex]
= [tex]\sqrt{9+4}[/tex]
= [tex]\sqrt{13}[/tex]
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