Question

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
A(n)=-6+(n-1)(1/5)

A)-6,-5 1/5, -4
B)5,-5 1/5, 1 4/5
C)-6, -5 2/5, -4 1/5
D) 0, 3/5, 1 4/5

Answer 1

Answer:

The answer is option C.

-6, -5 2/5, -4 1/5

Step-by-step explanation:

The arithmetic sequence is given by

$A(n) = - 6 + (n - 1)( \frac{1}{5} )$

where n is the number of terms

For the first term

n = 1

So we have

$A(1) = - 6 + (1 - 1)( \frac{1}{5} )$

$= - 6 + (0)( \frac{1}{5} )$

$= - 6$

For the fourth term

n = 4

$A(4) = - 6 + (4 - 1)( \frac{1}{5} )$

$= - 6 + (3)( \frac{1}{5} )$

$= - 5 \frac{2}{5}$

For the tenth term

n = 10

$A(10) = - 6 + (10 - 1)( \frac{1}{5} )$

$= - 6 + (9)( \frac{1}{5} )$

$= - 4 \frac{1}{5}$

Hope this helps you