Answer:
8
Step-by-step explanation:
[tex]Hypotenuse = 8\sqrt{2} \\Adjacent =x\\\alpha =45\\\\Using\: SOHCAHTOA\\Cos \alpha = \frac{Adjacent}{Hypotenuse}\\\\Cos 45 = \frac{x}{8\sqrt{2} } \\\frac{\sqrt{2} }{2} =\frac{x}{8\sqrt{2} }\\ \\Cross \: Multiply\\2x =16\\\frac{2x}{2} =\frac{16}{2} \\\\x =8[/tex]
