Answer:
=355.5K
Explanation:
Specific heat, Q = mcΔT
where
[1 mole of Ne = 20g; 2 moles of Ne = 2 × 20 = 40g]
4250 = 40 × 1.7 × (final - 293K)
final - 293k = 4250 / ( 40 × 1.7)
Final temp = 62.5 + 293
=355.5K
I hope this steps are simple to follow and understand.