Question

A light ray in air strikes water at an angle of incidence equal to 40°. If the index of refraction for water is 1.33, what is the angle of refraction?

Answer 1

Answer:

The angle of refraction is 28.68°

Explanation:

Given data

angle of incidence, i=40°

angle of refraction,r = ?

index of refraction u=  1.33

applying the formula

$u=\frac{ sin i}{ sin r}$

According to Snell's law, the incident, normal and refracted rays all act on the same point.

Substituting and solving for r we have.

$1.33= \frac{sin (40)}{sin (r)} \\\\sin(40)= 1.33* sin(r)\\\0.642= 1.33* sin(r)$

divide both sides by 1.33 we have

$sin(r)= \frac{0.642}{1.33} \\\sin(r)= 0.48\\\r= sin^-^10.48\\\r= 28.68$

r= 28.68°